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10=-4.9x^2-22x+65
We move all terms to the left:
10-(-4.9x^2-22x+65)=0
We get rid of parentheses
4.9x^2+22x-65+10=0
We add all the numbers together, and all the variables
4.9x^2+22x-55=0
a = 4.9; b = 22; c = -55;
Δ = b2-4ac
Δ = 222-4·4.9·(-55)
Δ = 1562
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-\sqrt{1562}}{2*4.9}=\frac{-22-\sqrt{1562}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+\sqrt{1562}}{2*4.9}=\frac{-22+\sqrt{1562}}{9.8} $
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